In Parts A, B, C consider the following situation. In a baseball game the batter swings and gets a good solid hit. His swing applies a force of 12,000 N to the ball for a time of 0.70×10−3s. Part A Assuming that this force is constant, what is the magnitude J of the impulse on the ball?

J = 8.4 kg*m/s

Explanation:

The magnitude of the impulse, J, on the ball can be calculated using the following equation:

  (1)

Where:

F: is the force = 12000 N

t: is the time = 0.70x10⁻³ s

So, by entering the values above into equation (1) we can find the impulse on the ball:

Therefore, the impulse on the ball is 8.4 kg*m/s.

I hope it helps you!

i believe the answer would be:

d. violin, clarinet, french horn, and tuba

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg