The de Broglie relation λ=h/p can be rewritten in terms of the wave number k as p=kℏ. Recall that wave number is defined by k=2π/λ. Using the fact that λ=v/f, find the wave numbers k1 and k2 corresponding to frequencies f1 and f2. Express your answer as two expressions

k₁ = 2πf₁/v

k₂ = 2πf₂/v

Explanation:

Since the de Broglie relation λ=h/p (1 ) and momentum, p =kℏ (2)

From (1) p = h/λ = kℏ

So,  h/λ = kℏ

Hence, k = h/ℏλ  since ℏ = h/2π and wavelength, λ = v/f, substituting these two into k, we have

k = h/[(h/2π)(v/f)]

k = 2πf/v where k = wave number, f = frequency of wave and v = velocity of wave.

Now, for the first wave number k₁, k₁ = 2πf₁/v

for the second wave number k₂, k₂ = 2πf₂/v

well, you would divide 135 by 33 to get your answer. then that is how many seconds it would take. boardman should fly about 132 m or 4.090909090909091 seconds.