You are riding in an elevator on the way to the eighteenth floor of your dormitory. The elevator's upward acceleration is 1.91 m/s2. Beside you is the box containing your new computer; box and contents have a total mass of 29.0 kg. While the elevator is accelerating upward, you push horizontally on the box to slide it at constant speed toward the elevator door. Part A If the coefficient of kinetic friction between the box and elevator floor is 0.35, what magnitude of force must you apply

F = 80.1 N

Explanation:

The force applied on the box must at least be equal to the frictional force of elevator floor on the box. Therefore,

F = μR equation (1)

where,

F = Force applied on box

μ = coefficient of kinetic friction between box and elevator floor = 0.35

R = Normal Reaction = Weight of box and its contents = W

In this case since, the elevator is moving upward with constant acceleration. Therefore, the weight will be given as:

W = m(g + a)

where,

m = mass of box and contents = 29 kg

g = 9.8 m/s²

a = upward acceleration of elevator = 1.91 m/s²

Therefore,

W = R = (29 kg)(9.8 m/s² - 1.91 m/s²)

R = 228.81 N

Therefore, using values in equation (1), we get:

F = (0.35)(288.81 N)

F = 80.1 N

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge