A ball is thrown vertically downward with an initial speed of 12.0 m/s from a height of 10.0 m above the ground. Ignoring air resistance, what is the speed of the ball when it reaches the ground? (A) 18.5 m/s
(B) 14.6 m/s
(C) 14.0 m/s
(D) 12.8 m/s
(E) 12.0 m/s
Can you just take a picture of your work clearly because I have to show work. Thanks.

18.5 m/s

Explanation:

Take down to be positive.

Given:

Δy = 10.0 m

v₀ = 12.0 m/s

a = 9.8 m/s²

Find: v

v² = v₀² + 2aΔy

v² = (12.0 m/s)² + 2 (10 m/s²) (10.0 m)

v = 18.5 m/s

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.

as we know our atmosphere or air have different levels. every level has other gasses, and every gas has another permeability. when the light comes from lower permeability to higher permeability, it changes its direction. so that means that when the light comes from the moon to the earth, it changes it's direction many more times. it basically means that the shape of the light part of the moon is changed on the earth.

hope this ! this is not copied! search it up, it's free of plagiarism!