Physics, 09.06.2020 23:57 kathiaflores1215

What two variables is acceleration dependent on? What is the relationship between these variables and acceleration? (i. E. If you increase one variable what happens to the acceleration?)

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Answer from: brandy127

1. Unbalanced Force (If you increase force, the acceleration will increase)

2. Mass of Body (If you increase mass, the acceleration will decrease)

Explanation:

According to Newton's Second Law the acceleration produced in a body depends upon two variables. The law states that:

“When an unbalanced force is applied on a body then an acceleration is produced in it, in its own direction”

The magnitude of produced acceleration is directly proportional to the applied force and inversely proportional to the mass of body. Mathematically,

aαF

and, aα1/m

where,

a = acceleration

F = Unbalanced Force

m = Mass of Body

So, the acceleration increases when the unbalanced force increase and vice versa.

And the acceleration decreases when the mass of body increase and vice versa.

combining above equations:

aαF/m

a=(Constant)F/m

here,

Constant=1

therefore,

F=ma

Answer from: Quest

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Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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