A human expedition lands on an alien moon. One of the explorers is able to jump a maximum distance of 16.0 m with an initial speed of 2.90 m/s. Find the gravitational acceleration on the surface of the alien moon. Assume the planet has a negligible atmosphere. (Enter the magnitude in m/s2.)

Gravitational acceleration (g) = 0.4205 m/s²

Explanation:

Given:

Distance (R) = 20 m

Initial speed (u) = 2.90 m/s

Find:

Gravitational acceleration (g)

Computation:

⇒ Distance (R) = [Initial speed (u)]²/ Gravitational acceleration (g)

⇒ Gravitational acceleration (g) =  [Initial speed (u)]² / Distance (R)

⇒ Gravitational acceleration (g) = 2.90 ² / 20

⇒ Gravitational acceleration (g) = 8.41 / 20

⇒ Gravitational acceleration (g) = 0.4205 m/s²

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation:

1 a

2 b

3 b

4 d

5 d

6 d

explanation: