On February 6, 1971, Alan Shepard made history by becoming the first astronaut to play golf on the Moon. Using only one hand to swing the club because of his bulky space suit, Shepard still managed a long drive. Given the lack of an atmosphere on the moon and a gravitational acceleration of 1.6 m/s2, how far would the shot go with an initial velocity of 25 m/s and a launch angle of 35∘?
A. 367 m
B. 375 m
C. 382 m
D. 391 m

the answer is b ) square root of 5

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

0.11 m/s and 0.28 m/s should be correct