Una caja de 40.0 kg se desliza 4.00 m hacia arriba por un plano inclinado de 26° con respecto a la acción de una fuerza de 340 N paralela al plano. Si el coeficiente de fricción cinético entre las superficies es 0.250, calcula el trabajo neto realizado sobre el objeto.

W = 320.30 J

Explanation:

To calculate the net work done over the block you take into account all implied forces:

 (1)

The gravitational force and friction force are against the applied force F.

θ = 26°

F: applied force = 340N

Fg: gravitational force = Mg = (40.0kg)(9.8m/s^2) = 392N

Ff: friction force =

Next, you replace to obtain the net force:

Finally, the net work, for 4 m, is:

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)

double the distance = divide strength by 4