How much thermal energy does it take to raise the temperature of 4.5 kg of water from 12°C to 97° C? The specific heat of water is 1.68 kJ/(kg*^ C) Use Q=mg(T f^ - T i ) .

642.6 x 10³ J

Explanation:

Q = ms(  ) ; m is mass , s is specific heat and  is rise in temperature .

Putting the given data in the equation we get as follows

Q = 4.5 x 1.68 x 10³ x ( 97 - 12 )

= 642.6 x 10³ J .

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