Two convex lenses with focal lengths 10.0 cm and 20.0 cm are separated by 70.0 cm. An object is located at 15.0 cm to the left of the first lens. Use the equation to calculate q1, P2, q2, M1 and M2 as measured from the second lens, then describe the final image?

Explanation:

Let us consider image formation from first mirror

object distance u = - 15 cm

v = ?

f = 10 cm

1 / v - 1 / u = 1 / f

1 / v + 1 / 15 = 1 / 10

1 / v = 1 / 10 - 1 / 15

= .1 - .067

= .033

v = 30 cm

Magnification M1 = v / u = - 30 / 15 = - 2

This image will act as object for second mirror

object distance for second mirror

u = 70 - 30 = 40 cm

f = 20 cm

v = ?

1 / v - 1 / u = 1 / f

1 / v + 1 / 40 = 1 / 20

1 / v = 1 / 20 - 1 / 40

= .05 - .025

= .025

v = 40 cm

Magnification M2 = v / u

= - 40 / 40

= -1 .

overall magnification

M = M1 X M2

= -2 x -1

= + 2

Final image will be 2 times the object and it will be real and it will be erect with respect to object .

answer: the metamorphic rocks are formed when they are exposed to high pressure and high temperatures. this happens when one of the earth's plates comes in contact with the other plate by traveling in opposite directions, straight into each other or slipping under one another. the friction that is caused by this activity results in   melting of rocks and when it cools they are known as metamorphic rocks. this process needs a controlled amount of pressure and temperature otherwise it may turn into magma.