A 62.0 kg water skier at rest jumps from the dock into a 775 kg boat at rest on the east side of the dock. If the velocity of the skier is 4.50 m/s as she leaves the dock, what is the final velocity of the skier and boat?

v = 0.33 m/s

Explanation:

The final velocity of the skier and boat can be calculated by conservation of the lineal momentum:

Where:

m1: is the mass of the water skier = 62.0 kg

m2: is the mass of the boat = 775 kg

v1i: is the initial velocity of the water skier = 4.50 m/s    

v1f: is the final velocity of the water skier = ?

v2i: is the initial velocity of the boat = 0

v2f: is the final velocity of the boat = ?

Since the final velocity of the skier is the same that the final velocity of the boat, we have:      

Therefore, the final velocity of the skier and boat is 0.33 m/s.

I hope it helps you!

a is the best answer your welcome

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg