Suppose that you place an object along the principal axis of a concave spherical
mirror, exactly halfway to the center of the curvature (half of the radius). What will
the result be?
The image will appear larger than the object and right-side up.
O The image will appear smaller than the object and upside-down.
A clear image of that object won't be formed at all.
The image will be upside-down and appear to be behind the mirror.

The base of a 50-meter tower is at the origin; the base of a 50-meter tree is at (0, 50, 0). the ground is flat and the z-axis points upward. the following parametric equations describe the motion of six projectiles each launched at time t = 0 in seconds. (i) r (t) = (50 + t2)k (ii) r (t) = 2t2 j + 2t2k (iii) r (t) = 50 i + 50 j + (50 − t2)k (iv) r (t) = 2t j + (50 − t2)k (v) r (t) = (50 − 2t) i + 2t j + (50 − t)k (vi) r (t) = t i + t j + tk (a) which projectile is launched from the top of the tower and goes downward? at time t = , the projectile hits the ground at point (x, y, z) = . (b) which projectile hits the top of the tree?