Each of two long straight parallel wires separated by a distance of 16 cm carries a current of 20 A in the same direction. What is the magnitude of the resulting magnetic field at a point that is 10 cm from each wire?

B = 6.6825 × T

Explanation:

Given that: I = 20 A, distance between the wires = 16 cm = 0.16 m, magnetic field at a point 10 cm (0.10 m) from each wire can be determined by;

The magnetic flux density (B) in a straight current carrying wire, is given as;

         B =

Where: is the permeability of free space = 1.26× m kg/, I is the current through the wires, r is the distance between the wires.

      B = ( 1.26× × 20) ÷ (2× × (0.16 - 0.10))

         = 25.2 ×  ÷ 0.3771

      B  = 6.6825 × T

i'm just gonna leave this comment here, so i can get a challange done-

explanation:

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)