16.

A balloon with a radius of 16 cm has an electric charge of 4.25 × 10–9 C.

a. Determine the electric field strength at a distance of 40.0 cm from the balloon’s centre.

E=kq/r^2 (8.99 x 10^9) (4.25 x 10^-9) / (0.40)^2

=1492.5N/C

b. A balloon with a radius of 14 cm and an electric charge of 3.75 × 10–9 C is brought within the electric field of the larger balloon so their centres are 40.0 cm apart. Determine the magnitude of the electric force exerted by this electric field on the smaller balloon.

Explanation:

Electric field due to a charge at a distance r

E = k Q / r²

here Q = 4.25 x 10⁻⁹ C , r = 40 cm = .4 m , K = 8.99 x 10⁹

E = 8.99 x 10⁹ x  4.25 x 10⁻⁹ / .4²

= 238.8 N/C

b )

small ballon's centre lies at distance of 40 cm from the centre of bigger charged balloon so ,

force on smaller charged balloon

= k q₁ q₂ / r²

k = 8.99 x 10⁹ , q₁ = 4.25 x 10⁻⁹ , q₂ = 3.75 x 10⁻⁹

r = .4 m

F = 8.99 x 10⁹ x 4.25 x 10⁻⁹ x  3.75 x 10⁻⁹  / .4²

= 895.5 x 10⁻⁹ N .

magnitude of the electric force exerted by this electric field on the smaller balloon

= 895.5 x 10⁻⁹ N .

science is a systematic and logical approach to discovering how things in the universe work. true to this definition, science aims for measurable results through testing and analysis. science is based on fact, not opinion or preferences. the process of science is designed to challenge ideas through research.

explanation:

layer a is the exosphere and layer b is the thermosphere.   is the answer i think but i hope this .