If a plane is inclined at an angle 5o with the horizontal and a cylindrical metal is allowed to roll between two fixed height 92cm apart on the plane. Given that the acceleration of the cylinder to be (2gSinθ/3) and g as 9.8m/s2, the time of descent i

0.61 second.

Explanation:

So, from the question we are given the following useful parameters or data or information that is going to assist us in solving this question and they are;

(1). Inclination of plane, θ = 50°.

(2). ''The horizontal and a cylindrical metal is allowed to roll between two fixed height 92cm apart on the plane" that is height = 0.92 m(92cm).

(3). The "acceleration of the cylinder to be 2/3 × g Sin (theta) and g = Acceleration due to gravity = 9.8m/s^2

Soz let us delve right into the solution to the question above. We will be making use of the mathematical representation or Equation below;

s = (1/2) a × t².

Where s = height, a = acceleration due to gravity and t = time.

0.92 = (9.8 × sin 50°/ 3) × t².

t² = 0.37

t = √ 0.37.

t =0.61 seconds.