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![|\vec{F_B}|=Isin\theta\int_0^{0.25}B(y)dy=Isin\theta\int_0^{0.25}(0.5y)dy\\\\|\vec{F_B}|=(2.0*10^{-3}A)(sin36.86\°)(0.5T)[\frac{0.25^2}{2}m]=0.187\ N](/tpl/images/0652/7983/50dc2.png)
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A wire lying along a y axis form y=0 to y=0.25 m carries a current of 2.0 mA in the negative directi...
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