3.7.6. A satellite is in a circular orbit around the Earth. If it is at an altitude equal to twice the radius of the Earth, 2RE, how does its speed v relate to the Earth's radius RE, and the magnitude g of the acceleration due to gravity on the Earth's surface?a)b)c)d)e)

Explanation:

For acceleration due to gravity

g = GM / R²   ( 1 )

At height 2R , radius of orbit is 3R .

If speed of satellite be v

m v² / 3R = GMm / (3R)² ( centripetal force = gravitational force )

v² = GM / 3R ( 2 )

Dividing (1) and (2)

v² / g = R / 3

v² = gR / 3

v = √( gR / 3 )

nah.   i'm just sleepy.

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.