A student locates a double-slit assembly 1.40 m from a reflective screen. The slits are separated by 0.0572 mm. (a) Suppose the student aims a beam of yellow light, with a wavelength of 589 nm, toward the slit assembly, and this makes an interference pattern on the screen. What distance (in cm) separates the zeroth-order and first-order bright fringes (a. k.a. maxima)?

Complete Question

A student locates a double-slit assembly 1.40 m from a reflective screen. The slits are separated by 0.0572 mm.

(a) Suppose the student aims a beam of yellow light, with a wavelength of 589 nm, toward the slit assembly, and this makes an interference pattern on the screen. What distance (in cm) separates the zeroth-order and first-order bright fringes (a.k.a. maxima)?

(b)

Now suppose that blue light (with

λ = 415 nm)

is used instead. What distance (in cm) will now separate the second-order and fourth-order bright fringes?

a

The distance of separation is  

b

The distance of separation is  

Explanation:

From the question we are told that

     The distance from the screen is  

      The slit separation is

       The wavelength of the yellow light is  

The distance of a fringe from the central maxima is mathematically represented as

Where n is the order of the fringe so the distance of separation between  

   The distance that separates first order from zeroth order bright fringe can be evaluated as

Substituting values

Converting to cm

b

The  wavelength of blue light is  

       So the distance that separates second  order from fourth order bright fringe can be evaluated as

Substituting values

Converting to cm

potential energy is directly proportional to height.

more height = more potential energy.

greatest increase in height = greatest increase in potential energy

where are the points with the greatest increase in height ?

has to be c-e or d-e .

0.19 m/s and 0.45 m/s