The Velocity-Time graphs of the two cars, K and I are given
below together. If the cars start their journey together and they
have a position difference of 10 m at time t, what will be the
position difference between them at time 4t at the end?

The position difference between them at time 4t is 10m.

Explanation:

A velocity-time graph illustrate the movement of an object from one location to another given some of its parameters. The slope of the graph gives the acceleration of the object, and the total area under the graph gives the total distance covered by the object.

From the given graph, the starting points for both cars are not the same neither their stopping point. Initially, the starting position difference between the cars is 10m. The position difference between them at time 4t at the end is 10m.

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!