Physics, 05.05.2020 06:34 Sinless60951

(n = 1.33). When visible light (400nm – 700 nm) shines normally on the film an observed from above, the bright reflected light looks kind of "purplish" with red light of wavelength 650 nm mixed some blue giving it that appearance and "greenish" light of wavelength 520 nm is completely destroyed. Determine the thickness of the acetone film. (you only need to worry about the red and green wavelengths, not the blue)

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Answer from: datboyjulio21

Complete Question

A thin film in air is made by putting a thin layer of acetone (n = 1.25) on a layer of water

(n = 1.33). When visible light (400 nm – 700 nm) shines normally on the film an observed from above, the bright reflected light looks kind of “purplish” with red light of wavelength 650 nm mixed some blue giving it that appearance and “greenish” light of wavelength 520 nm is completely destroyed. Determine the thickness of the acetone film. (you only need to worry about the red and green wavelengths, not the blue)

The thickness of acetone is d = 104 nm

Explanation:

A diagram showing this process is shown on the first uploaded image

From the question we are told that

The refractive index of acetone is n_a =1.25

The refractive index of water is n_w = 1.33

The wavelength of the reflected light is $\lambda_r = 650nm = 650 *10^{-9}m$

The wavelength of the destroyed light is $\lambda_g = 520nm = 520 *10^{-9}m$

Looking at the given data we can see that the

n_a < n_w

This means that the light which the acetone-water layer would reflect will have a phase shift of $\pi$

Again this make us to understand that the light reflected at the acetone layer will also have a phase shift of $\pi$

Since they would be having the same phase shift the two light would interfere

For interference the condition for minima is mathematically represented as

$2 n_a d = (m + \frac{1}{2} ) \lambda_g$

Where d is the thickness of acetone

$d = \frac{\lambda_g}{4 n_a}$

Substituting values

$d = \frac{520 *10^{-9}}{4 * 1.25}$

$d = 104 *10^{-9}m$

d = 104 nm

(n = 1.33). When visible light (400nm – 700 nm) shines normally on the film an observed from above,

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they are non-matter. basically, any type of energy or any abstract concept is an example of something that does not matter. other examples include dreams, magnetism, radio, and hate

Answer from: Quest

explanation:

as the height from which the ruler was dropped increased, the speed of the ruler at ryan's hand increased.

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