The rate of change of the downward velocity of a falling object is the acceleration of gravity (10 meters/sec^2) minus the acceleration due to air resistance. Suppose that the acceleration due to air resistance is 0.2 inverse seconds times the downward velocity. Write the initial value problem and the solution for the downward velocity for an object that is dropped (not thrown) from a great height. dv dt

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energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j