The small piston of a hydraulic lift, has an area of 0.01m2. If a force of 250N is applied to the small piston if it has an area of 0.05m2.
Critical Thinking

Explanation:

Given that,

Small piston Hydraulic piston has an area

A1 = 0.01m²

If the force applied is 250N is applied to the small piston at an area of 0.05 m²

Then,

F2 = 250 N and A2 = 0.05m²

Then, applying pascal principle,

Pressure at small area = pressure are bigger area

P1 = P2

F1 / A1 = F2 / A2

F1 / 0.01 = 250 / 0.05

F1 / 0.01 = 5000

Cross multiply

F1 = 5000 × 0.01

F1 = 50 N

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