7. A person pushes on a 5.00 kg box with a force of 15.0 N to the right. As a result, the box moves at a constant speed of 10.0 m/s.

Answer

Given,

Mass of the box, m = 5 kg

Force, F = 15 N

Speed of the box, v = 10 m/s

Assuming we need to determine weight, normal force, and the frictional force on the box.

Weight of the box = m g = 5 x 9.8 = 49 N

Normal force on the box =  Weight of the box = 49 N.

Frictional force on the box will be equal to 15 N because box is moving with constant velocity.

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

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