A charged particle is placed in a uniform magnetic field and negligible gravitational field. When released it will exhibit constant

Constant velocity

Explanation:

The Lorentz force acting on the particle is given by F = Bqvsinθ where B =    magnetic field strength, q = charge, v = speed of charge and θ = angle between v and B.

If the charge is released with a velocity, v, it experiences a force, F = Bqvsinθ. Since F = ma, Bqvsinθ = ma and a = Bqvsinθ/m. So, since all the variables are constant, the charged particle exhibits no acceleration since the velocity is constant.

b

step-by-step explanation: a third of 24 is 8, 8 times 3 is 24 so 8 - 2 would be 6

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.