Two identical charges , 2.0m apart , exert forces of magnitude 4.0N on each other . The value of either charge is : ( ke= 9*10^9 N. M^2 .C^-2)

4.216 * 10^(-5) C

Explanation:

Parameters given:

Electrostatic force between charges, F = 4N

Distance between the charges, r = 2 m

The electrostatic force acting between two charged particles, q1 and q2, separated by a distance, r, is given as:

F = (k * q1 * q2) / r²

Where k = Coulombs constant.

Since q1 = q2 = q,

F = (k * q²) / r²

Inputting all the values:

4 = (9 * 10^9 * q²) / 2²

=> 16 = (9 * 10^9 * q²)

=> q² = 16 / (9 * 10^9)

q² = 1.78 * 10^(-9)

=> q = 4.216 * 10^(-5) C

The value of both charges is 4.216 * 10^(-5) C.

answer; ///(c); ///bronchi i do believe this is the correct answer,; plz check first..good luck

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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