Acar traveling at a speed of 13 meters per second accelerates uniformly to a speed of 25 meters per second in 5.0 seconds.
a truck traveling at a constant speed covers the same total distance as the car in the same 5.0 second interval. determine the speed of the truck.
calculate the magnitude of the accelerate of the car during this 5.0 second interval.

1) Acceleration of the car: 2.4 m/s^2

Explanation:

The acceleration of the car is given by:

where

v = 25 m/s is the final velocity of the car

u = 13 m/s is the initial velocity

t = 5.0 s is the time taken

Substituting the numbers into the equation, we find

2) Speed of the truck: 19 m/s

First of all, we need to find the total distance covered by the car, which is given by the equation:

The truck covers the same distance in t=5.0 s, travelling at constant speed; therefore, its speed is given by

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.