For a certain optical medium the speed of light varies from a low value of 1.80 × 10 8 m/s for violet light to a high value of 1.92 × 10 8 m/s for red light. Calculate the range of the index of refraction n of the material for visible light.

1.56 - 1.67

Explanation:

Refractive index of any material is given as the ratio of the speed of light in a vacuum to the speed of light in that medium.

Mathematically, it is given as:

n = c/v

Where c is the speed of light in a vacuum and v is the speed of light in the medium.

Given that the speed of light in the optical medium varies from 1.8 * 10^8 m/s to 1.92 * 10^8 m/s, we can find the range of the refractive index.

When the speed is 1.8 * 10^8 m/s, the refractive index is:

n = (3 * 10^8) / (1.8 * 10^8)

n = 1.67

When the speed is 1.92 * 10^8 m/s, the refractive index is:

n = (3 * 10^8) / (1.92 * 10^8)

n = 1.56

Therefore, the range of values of the refractive index of the optical medium is 1.56 - 1.67.

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.

t = 1/400 h   ⇔ 0.0025 h ⇔ 9s ⇔ 0.15 m

any of the answers are correct.