What kind of image is formed by an object that is placed beyond the center of curvature on the principal axis of a concave mirror?
A. real, inverted, the same size as the object, and at the same distance as the object
B. real, inverted, larger than the object, and farther from the mirror than the object
C. virtual, upright, left-right reversal, the same size as the object, and at the same distance as the object
D. real, inverted, smaller than the object, and closer to the mirror than the object
E. virtual, upright, larger than the object, and farther from the mirror than the object

D.   real, inverted, smaller than the object, and closer to the mirror than the object

Explanation:

When the object is located at a location beyond the center of curvature, the image will always be located somewhere in between the center of curvature and the focal point. Regardless of exactly where the object is located, the image will be located in the specified region. In this case, the image will be an inverted image. That is to say, if the object is right side up, then the image is upside down. In this case, the image is reduced in size; in other words, the image dimensions are smaller than the object dimensions. If the object is a six-foot tall person, then the image is less than six feet tall. Earlier in Lesson 2, the term magnification was introduced; the magnification is the ratio of the height of the image to the height of the object. In this case, the absolute value of the magnification is less than 1. Finally, the image is a real image. Light rays actually converge at the image location. If a sheet of paper were placed at the image location, the actual replica of the object would appear projected upon the sheet of paper.

hi there!

out of the two, (b) precision would be more reasonable.   however, both a and b could be pretty reasonable.

-awesomerepublic   : )