Two cars are traveling on a desert road, as shown below. after 5.0 s, they are side by side at the next telephone pole. the distance between the poles is 85.5 m.
(a) the displacement of car a after 5.0 s
m
(b) the displacement of car b after 5.0 s
m
(c) the average velocity of car a during 5.0 s
m/s
(d) the average velocity of car b during 5.0 s
m/s

The answer is:

a)  the displacement of car A after 5.0 s  = 85.5 m

b)  the displacement of car B after 5.0 s  = 171 m

C) the average velocity of car A during 5.0 s =17.1 m/s

d) the average velocity of car B during 5.0 s  = 34.2m/s

The explanation:

a) when car B was away car A about 85.5 m and after 5 s it reaches car B SO car A need a displacement a bout 85.5m to reach Car B

So our answer here will be 85.5 m.

b) and when car B is going in the same velocity and car A has reached it by displacement 85.5 so the displacement of car B will be = 85.5 * 2 = 171 m

c) when the average velocity = displacement (carA) / time

                                                = 85.5 m / 5 s = 17.1 m/s

d) and the average velocity for car B = displacement (carB) / time

                                                             = 171m / 5s = 34.2 m/s

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note: the given question is incomplete.

complete question is given below.

which is an example of kinetic energy?

a. the energy stored in ethanol  

b. a hockey puck sliding across the ice  

c. a compressed spring  

d. a ball sitting at the top of a ramp

solution: the kinetic energy is the energy posses by the virtue of the motion of the object.

in the given options, a, c and d are the example of potential energy because it is the energy posses by the virtue of the rest of the object. but option b has the kinetic energy as the object is in motion.

hence, a hockey puck sliding across the ice   is the apex example of kinetic energy.

so, the option (b) a hockey puck sliding across the ice   is the correct option.