Car A, is is traveling to the right toward an intersection at a constant rate of 12 m/s. Car B, is sitting at the light waiting for it to turn green. At the instant the light turns green, Car A is 50 m away from the light and Car B begins to accelerate at a rate of 1.8 m/s2 . At what point in time will Car A pass Car B? At what point in time will Car B pass Car A (hint this is due to car be still accelerating.)? How far from the light will they be each time they are passing eachother?

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

Amethod of procedure that has characterized natural science since the 17th century, consisting in systematic observation, measurement, and experiment, and the formulation, testing, and modification of hypotheses.

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