A battery with emf 10.30 V and internal resistance 0.50 Ω is inserted in the circuit at d, with its negative terminal connected to the negative terminal of the 8.00-V battery. What is the difference of potential Vbc between the terminals of the 4.00-V battery now?

Explanation:

Given that,

Battery EMF is

V = 10.3 V

The battery has an internal resistance of

r = 0.50 Ω

Question not complete

Check attachment for solution and circuit diagram

3.78V

Explanation:

The resistance in the circuit is

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