An alpha particle (q = +2e, m = 4.00 u) travels in a circular path of radius 4.29 cm in a uniform magnetic field with B = 1.53 T. Calculate (a) its speed, (b) its period of revolution, (c) its kinetic energy, and (d) the potential difference through which it would have to be accelerated to achieve this energy.

A) speed = 3144287.425 m/s

B) period = 8.57x10^-8 s

C) KE = 3.302x10^-14 J

D) potential difference = 103187.5 V

Explanation:

Detailed explanation and calculation is shown in the image below.

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach

conduct current i mean it makes sense