Bert is making a strawberry milkshake in his blender. A tiny, 5.0 g strawberry is rapidly spun around inside of the container with a speed of 14.0 m/s, held by a centripetal force of 10.0 N. What is the radius of the container at this location?

Explanation:

Given that,

Mass of strawberry

m = 5g = 0.005kg

Speed at which it is spun in a circular motion

v = 14m/s

Centripetal force that held it in motion

Fc = 10N

Radius of circular motion r?

Centripetal force is given as

Fc = m•ac

Where m is mass

And ac is centripetal acceleration.

Then, centripetal acceleration is give as

ac = v²/r.

So,

Fc = mv²/r

Making r subject of formulas

r = mv² / Fc

Where,

m is mass m = 0.005kg

v is velocity v = 14m/s

Fc is centripetal force Fc = 10N

Then,

r = mv² / Fc.

r = 0.005 × 14² / 10

r = 0.098m

r = 9.8cm

The radius of the path of circular motion is 9.8cm

fgravity=10x10=100n case 1

fgravity=30x20=600n case 2

6 times more

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west