The Mistuned Piano Strings Two identical piano strings of length 0.800 m are each tuned exactly to 480 Hz. The tension in one of the strings is then increased by 1.0%. If they are now struck, what is the beat frequency between the fundamentals of the two strings? SOLUTION Conceptualize As the tension in one of the strings is changed, its fundamental frequency changes. Therefore, when both strings are played, they will have different frequencies and beats be heard. Categorize We must combine our understanding of the waves model for strings with our new knowledge of beats.

Complete Question

The complete question is shown on the first uploaded image

The answer is

      % higher than

    % lower than

Explanation:

   From the question we are told that

         The first string has a frequency of  

          The period of the beat is  

Generally the frequency of the beat is

  Substituting values

From the question

          for    having a  higher tension

So

 From the question

Substituting values

      % higher than

    For having a lower tension

  So

  From the question

    Substituting values

      % lower than        

i think it’s a. this is because if they measured the mass of something with a mass of 150g, then their final answer would have to be approximately 150g. though all of their answers are almost 150, rosa and tran have the closest answers (or the exact answer) to the accurate one.

float.

archimedes' principle

denser than water sinks in water.

denser than mercury would sink in it