2. An object with moment of inertia 1 = 9.7 x 10−4 kg ∙ m2 rotates at a speed of 3.0 rev/s. A 20 g mass with moment of inertia 2 = 1.32 x 10−6 kg ∙ m2 is dropped onto the rotating object at a distance of 5.0 cm from the center of mass. What is the angular velocity of the combined object and mass after the drop?

2.85 rad/s

Explanation:

5 cm = 0.05 m

20 g = 0.02 kg

When dropping the 2nd object at a distance of 0.05 m from the center of mass, its corrected moments of inertia is:

So the total moment of inertia of the system of 2 objects after the drop is:

From here we can apply the law of angular momentum conservation to calculate the post angular speed

jupiter

explanation:

it is so massive and has such a strong gravitational pull its likely prevented the formation of a planet between itself and mars in the asteroid belt

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