The International Space Station is orbiting at an altitude of about 370 km above the earth's surface. The mass of the earth is 5.976 × 1024 kg and the radius of the earth is 6.378 × 106 m. Assuming a circular orbit, what is the period of the International Space Station's orbit?

T = 5516.63 seconds

Explanation:

Given that,

The International Space Station is orbiting at an altitude of about 370 km above the earth's surface.

Mass of the Earth,

Radius of Earth,

We need to find the period of the International Space Station's orbit. It is a case of Kepler's third law. Its mathematical form is given by :

R = r + h

So, the period of the International Space Station's orbit is 5516.63 seconds.

i will answer your question if you answer mine