Ernest Rutherford (who was the first person born in New Zealand to be awarded the Nobel Prize in chemistry) demonstrated that nuclei were very small and dense by scattering helium-4 nuclei (4He) from gold-197 nuclei (197Au). During this experiment, the energy of the incoming helium nucleus was 8.00 × 10^-13 J, and the masses of the helium and gold nuclei were 6.68 × 10^-27 kg and 3.29 × 10^-25 kg, respectively (note that their mass ratio is 4 to 197).

a. If a helium nucleus scatters to an angle of 1200 during an elastic collision with a gold nucleus, calculate the helium nucleus's final speed and the final velocity (magnitude and direction) of the gold nucleus.
b. What is the final kinetic energy of the helium nucleus?

the velocity of the gold nuclei  

the angle of the velocity of gold nuclei = 29.64° clockwise (i.e down the horizontal)

the final kinetic energy of helium nucleus is

Explanation:

The formula for kinetic Energy (K.E) is:

where;

= mass of the helium

= velocity of helium

replacing and ; we have :

Applying conservation of momentum along x- axis since the collision is elastic

        ------ equation (1)

where

= mass of helium and gold respectively

= initial velocity of helium

= final velocity of gold

= scattered angle for helium  and gold respectively

Along the y - axis; the equation for conservation of momentum is :

 ---- equation (2)

Equating equation (1) and (2); we have:

   ----- equation (3)

However, the conservation of internal kinetic energy guves:

Making the subject of the formula ; we have:

     ----- equation (4)

Replacing the expression of in equation (3) into equation (4) ; we have

In the above expression;

replacing ;

;   ;   ;  ; we have:

The above is a quadratic equation; now solving by using the quadratic formula; we have:

since we are considering the positive value from the above expression; we have

NOW; we substitute our known values into equation (4) in order to solve for ; we have:

Therefore; the velocity of the gold nuclei  

From equation (2)

Therefore replacing our known values and solving for ; we have:

∴ the angle of the velocity of gold nuclei = 29.64° clockwise (i.e down the horizontal)

b) Equation to determine the final kinetic energy of helium is:

=

Thus, the final kinetic energy of helium nucleus  is

I hope this explanation helps alot!.

pretty sure it's false