A chemist must dilute 58.00ml of 13.5 aqueous silver(II) oxide solution until the concentration falls to 5.00M. He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in milliliters. Round your answer to 3 significant digits.

Explanation:

The given solution of silver oxide = 58 ml of 13.5 M of silver oxide

When we increase its volume , its molar concentration becomes less . To calculate the concentration of diluted solution , we can apply the following relation .

S₁ V₁ = S₂ V₂ .

S₁ is molar strength when volume is V₁ . S₂ is molar strength when volume is V₂

Puting the given values in the formula above ,

58 x 13.5 M = V₂ x 5

V₂ = 58 x 13.5 / 5

= 156.6 ml .

= 157 ml after rounding off.

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.

answer: a. same unit

explanation: