Use the graph below to answer the following question:

Graph titled maximum kinetic energy of ejected photo electron versus incoming frequency is shown. The y axis is labeled maximum kinetic energy and scales from negative 3 to positive 3 electron volts. The x axis is labeled frequency from 0 to 11 times 10 to the 14 hertz. A line connects the points 0, negative 2 and 2.5, negative 1 and 5, 0 and 8, 1 and 10, 2.

What is the threshold frequency of the experimental photo-missive material?

10.0 × 1014 Hz
5.0 × 1014 Hz
2.6 × 1014 Hz
0.5 × 1014 Hz

Answerapplying a direct current to a non magnetic material in order to create a electromagnetic field; plz check first good luck;

Answer: a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same sign as the  -4.0  µc charge.======electricstatic force between two point charges  is given by    where k is coulomb's constant,  8.99×10⁹  n·m²/c², q₁ and q₂ are the point charges, and r is the distance between the two point charges.assign positive to q₁let q₁ =  6.0 µc, q₂ = -4.0  µc, q₀ represent the charge at the origin, and q₃ represent this new charge to place.the charge at the origin q₀ would experience the following force f₀₁ from q₁, with r = 6.0 m (note that 1  µc = 10⁻⁶ c)    the force from q₂    the force from q₃    the net force on the origin charge, q₀, has to be zero for no electrostatic forcehaving an equation where k and q₀ can be divided out of the equation will allow us to solve for q₃    isolating:     a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same as the  -4.0  µc charge