An object is thrown with a horizontal velocity of 20 m/s from a cliff that is 125 m above level ground. If air resistance is negligible, the time that it takes the object to fall to the ground from the cliff is most nearly

The time taken for the object to fall to the ground is 5 s

From the question given above, the following data were obtained:

The time taken for the object to fall to the ground can be obtained as follow:

Therefore, the time taken for the object to get to the ground is 5 s

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Given that,

Horizontal velocity of the object, v = 20 m/s

Height of the cliff, h = 125 m

We need to find the time that it takes the object to fall to the ground from the cliff is most nearly. It can be calculated using second equation of motion. Let us consider that the initial speed of the object is 0. So,

Here, a = g and u = 0

So, the object will take 5 seconds to fall to the ground from the cliff.

it is called kinetic energy

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards