Pool ball moving is with velocity of 1.5 m/s. It hits a second pool ball of equal mass, initially at rest. After the collision the first ball moves off at 370 angle from its original direction with a speed of 1 m/s. Find the velocity (magnitude and direction) of the second ball after the collision.

it becomes positively charged by charging it

neither accurate nor precise.

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s