A motor is connected to the smaller 0.2 m radius pulley and cable, lifting 150 kg mass. Neglecting the mass/weight of the cable and pulley(s), find the torque necessary to accelerate the mass from 0 ms to 10 ms in 10 s (assume linear). Q4. 198.1 [Nm](a) 236.2 [Nm](b) 324.3 [Nm](c) 491.1 [Nm]

324.3Nm

Explanation:

The torque is given by the equation

in this case the vectors r and F are perpendicular between them, thus:

The forces acting on the mass are:

   (1)

where T is the tension of the cable, M is the mass and a is the acceleration.

Furthermore, we have that the acceleration is:

By replacing in (1) we can obtain:

The force T produces the torque on the pulley, hence:

the answer is 324.4Nm

hope this helps!

= initial pressure

= final pressure = 2

= initial volume

= final volume = /4

= initial temperature = 20 c = 20 + 273 = 293 k

= final temperature = ?

using the equation