Two long parallel wires are separated by 18 cm. One of the wires carries a current of 8 A and the other carries a current of 26 A. The permeabilty of free space is 1.257 × 10−6 N · m/A. Determine the magnitude of the magnetic force on a 2.1 m length of the wire carrying the greater current.

The magnitude of the magnetic force on the wire carrying greater current is is 4.85 x 10⁻⁴ N

Explanation:

Given;

distance of separation of the two wires, d = 18 cm

current in the first wire, I₁ = 8 A

current in the second wire, I₂ = 26 A

length of the wire, L = 2.1 m

permittivity of free space, μ₀ = 4π x 10⁻⁷ N·m/A = 1.257 × 10⁻⁶ N·m/A

The magnitude of the magnetic force on the wire carrying greater current is given as;

Therefore, the magnitude of the magnetic force on the wire carrying greater current is is 4.85 x 10⁻⁴ N

i had this question and the answer was 3.15 miles.

martina travels from school to her mom's office. from there, she walks to school. after school, she walks to the library and then to a friends house before finally ending back at home. find martina's total distance traveled.

a) 0 miles  

b) 0.4 miles  

c) 1 mile  

d) 3.15 miles