Capacitors A and B are two identical capacitors that store different amount of energy. A stores 6.2x 10-3J and B stores 6.8 x 10-4J. The voltage across the plates of capacitor B is 15 V. Find the voltage across the plates of capacitor A.

45.31 V.

Explanation:

From the question, since capacitor A and capacitor B are Identical, Then both Capacitor A and Capacitor B have the same Capacitance.

I.e

Ca = Cb = C

Where Ca = capacitance of Capacitor A, Cb = Capacitance of capacitor B.

Using,

Eb = 1/2C(Vb)² Equation 1

Where Eb = energy stored in capacitor B, Vb = Voltage of capacitor B

make C the subject of the equation

C = 2Eb/(Vb)² Equation 2

Given: Eb = 6.8×10⁻⁴ J, Vb = 15 V

Substitute into equation 2

C = 2(6.8×10⁻⁴)/15²

C = 6.04×10⁻⁶ F.

Similarly,

Using,

Va = √(2Ea/C) Equation 3

Where Va = Voltage Across the plates of Capacitor A, Ea = Energy stored in capacitor A.

Given: Ea = 6.2×10⁻³ J, C = 6.04×10⁻⁶ F

Substitute into equation 3

Va = √(2×6.2×10⁻³/6.04×10⁻⁶)

Va = √(2052.98)

Va = 45.31 V.

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force