Determine W (or fuel energy) required to launch a satellite of mass m at rest from a launching pad placed at the surface earth, to a circular orbit where the radius of the orbit is r = 5 R where R is the radius of the earth. Ignore the effect of the Earth’s rotation. Take the mass of the Earth to be M. The fuel energy required is:.
1. 5GmM/ (4R)
2. 3GmM/(2R)
3. 7GmM/(6R)
4. 2GmM/R
5. 9GmM/(10R)
6. 5GmM/(6R)
7. 11GmM/(10R)
8. 3GmM/(4R)

5. 9GmM/(10R)

Explanation:

m is the mass of the satellite

M is the mass of the earth

W is the energy required to launch the satellite

Energy at earth surface = Potential energy (PE) + W

W = Energy at earth surface - Potential energy (PE)

But PE =

Therefore: W = Energy at earth surface -

Energy at earth surface (E) at an altitude of 5R =

But

Therefore:

W = E - PE

they are non-matter

explanation:

they are non-matter. basically, any type of energy or any abstract concept is an example of something that does not matter. other examples include dreams, magnetism, radio, and hate

hello, i am papaguy.

i have found an answer to your question but use it as information.

information: because weak acids/bases have low concentration of hydrogen ions, the addition of water has a large impact on the ph. 2. a difference in 1 unit is a 10x difference in concentration for example; a liquid with ph of 3 is 10x more acidic than a liquid with a ph of 4. therefore, a liquid with a ph of 3 is stronger.

best of luck!