An automobile of mass 1900 kg is supported by a hydraulic lift having a large piston of cross-sectional area 10 m 2. The mechanic has a foot pedal attached to a small piston of cross-sectional area 0.5 m2. What force in Newtons must be applied to the small piston to raise the automobile

The force must be applied to the small piston to raise the automobile = 932 N

Explanation:

Given data

Mass = 1900 kg

Force = m g

Force = 1900 × 9.81 = 18639 N

Area of larger Piston = 10

Area of smaller Piston = 0.5

Force on smaller piston =

From the equilibrium

Pressure on larger piston = Pressure on smaller piston

= 932 N

Therefore the force must be applied to the small piston to raise the automobile.

idk sorry i only needs point for apex

explanation:

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.