A car drives 5.0 km north, then 7.3 km east, then 5.3 km northeast, all at a constant velocity. If the car had to perform 2.6 × 106 J of work during this trip, what was the magnitude of the average frictional force on the car?

147.73N

Explanation:

Work is said to be done if an applied force causes a body to move through a distance.

Work done by the car = Force × distance.

Given:

Work done = 2.6 × 10^6 Joules

Total distance covered by the car = 5.0km + 7.3km + 5.3km

= 17.6km

= 17600m

From the formula:

Force = Work done/Total distance

Force = 2.6×10^6/17600

Force experienced by the car = 147.73N

Magnitude of the average frictional force on the car is 147.73N

the answer is d. 4

hope this

also the more points you give the faster your questions get answered

hi there!

out of the two, (b) precision would be more reasonable.   however, both a and b could be pretty reasonable.

-awesomerepublic   : )