5 single loop of copper wire, lying flat in a plane, has an area of 8.60cm2 and a resistance of 3.00. A uniform magnetic field points perpendicular to the plane of the loop. The field initially has a magnitude of .5 T, and the magnitude increases linearly to 3. 0 in a time of 1.10 s, what is the induced current in the loop of wire over this time? .652A

0.652 mA

Explanation:

According to Faraday's Law :

where ;

A =

Induced current  I =

=

=

= 0.652 mA

Thus, the induced current in the loop of wire over this time = 0.652 A

none, its a machine

when a device is used in a circuit in which the voltage is 81 v, the current flowing through the device is 3 a. what is the resistance of the device?

a. 27 ω

b. 40.5 a

c. 243 ω

d. 243 a

the correct answer is a. 27