A beam of light is incident from air on the surface of a liquid. If the angle of incidence is 38.0° and the angle of refraction is 26.5°, find the critical angle for total internal reflection for the liquid when surrounded by air.

The critical angle for total internal reflection for the liquid when surrounded by air is 46.8 degrees.

Explanation:

Given that,

Angle of incidence, i = 38°

Angle of refraction, r = 26.5°

Firstly, we will find the refractive index of the liquid. It can be calculated using Snell's law as :

The relation between refractive index and critical angle for total internal reflection for the liquid is given by :

So, the critical angle for total internal reflection for the liquid when surrounded by air is 46.8 degrees.

gas and liquid

f=ma newton

f=100x2.5=250n