Oil having a density of 924 kg/m 3 floats on water. A rectangular block of wood 3.79 cm high and with a density of 970 kg/m3 floats partly in the oil and partly in the water. The oil completely covers the block. How far below the interface between the two liquids is the bottom of the block

x = 2.69 cm

Explanation:

We are given ;

Density of oil; ρ_oil = 924 kg/m³

Density of wood; ρ_wood = 970 kg/m³

h = 3.79cm

Density of water ( ρ_water) has a constant value of 1000 kg/m³

At equilibrium position, we have;

ρ_wood•g•h - ρ_oil•g•(h - x) - ρ_water•g•x = 0

This is because the density of oil is lower than that of water while density of wood is higher than that of oil but lower than that of water.

x is the distance below the interface between the two liquids is the bottom of the block.

Thus, let's make x the subject;

x = [(ρ_wood - ρ_oil)/(ρ_water - ρ_oil)] x h

Plugging in the relevant values to get ;

x = [(970 - 924)/(1000 - 924)] x 3.79

x = (54/76) x 3.79 = 2.69cm

the answer for apex is the lowest

  the unit of the measure =

explanation:

  the property that is quantified by the energy needed per of material to raise the temperature by one.

  si unit of energy = joule (j)

  si unit of temperature = kelvin (k)

  si unit of mass of material = kilogram (kg)

the property that is quantified by the energy needed per of material to raise the temperature by one is called specific heat.

the unit of specific heat is